⭐️
# 題目敘述
There is a function signFunc(x)
that returns:
1
ifx
is positive.-1
ifx
is negative.0
ifx
is equal to0
.
You are given an integer array nums
. Let product
be the product of all values in the array nums
.
Return signFunc(product)
.
# Example 1
Input: nums = [-1,-2,-3,-4,3,2,1]
Output: 1
Explanation: The product of all values in the array is 144, and signFunc(144) = 1
# Example 2
Input: nums = [1,5,0,2,-3]
Output: 0
Explanation: The product of all values in the array is 0, and signFunc(0) = 0
# Example 3
Input: nums = [-1,1,-1,1,-1]
Output: -1
Explanation: The product of all values in the array is -1, and signFunc(-1) = -1
class Solution { | |
public: | |
int arraySign(vector<int>& nums) { | |
int sign = 1; | |
for (int n : nums) { | |
if (n == 0) return 0; | |
if (n < 0) sign *= -1; | |
} | |
if (sign > 0) return 1; | |
else return -1; | |
} | |
}; |
class Solution { | |
public int arraySign(int[] nums) { | |
int sign = 1; | |
for (int n : nums) { | |
if (n == 0) return 0; | |
if (n < 0) sign *= -1; | |
} | |
return sign > 0 ? 1 : -1; | |
} | |
} |
class Solution: | |
def arraySign(self, nums: List[int]) -> int: | |
sign = 1 | |
for n in nums: | |
if n == 0: return 0 | |
if n < 0: sign *= -1 | |
return 1 if sign > 0 else -1 |