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# 題目敘述
You are given an array of unique integers salary
where salary[i]
is the salary of the ith
employee.
Return the average salary of employees excluding the minimum and maximum salary. Answers within 10-5
of the actual answer will be accepted.
# Example 1
Input: salary = [4000,3000,1000,2000]
Output: 2500.00000
Explanation: Minimum salary and maximum salary are 1000 and 4000 respectively.
Average salary excluding minimum and maximum salary is (2000+3000) / 2 = 2500
# Example 2
Input: salary = [1000,2000,3000]
Output: 2000.00000
Explanation: Minimum salary and maximum salary are 1000 and 3000 respectively.
Average salary excluding minimum and maximum salary is (2000) / 1 = 2000
# Solution
class Solution { | |
public: | |
double average(vector<int>& salary) { | |
int mn = salary[0], mx = salary[0]; | |
double res = 0; | |
for (int s : salary) { | |
res += s; | |
mn = min(mn, s); | |
mx = max(mx, s); | |
} | |
res -= (mn + mx); | |
return res / (salary.size()-2); | |
} | |
}; |
import java.util.Arrays; | |
class Solution { | |
public double average(int[] salary) { | |
Arrays.sort(salary); | |
long sum = 0; | |
for(int i = 1; i < salary.length - 1; i++){ | |
sum += salary[i]; | |
} | |
return sum / (salary.length - 2 * 1.0); | |
} | |
} |
class Solution: | |
def average(self, salary: List[int]) -> float: | |
min_salary = min(salary) | |
max_salary = max(salary) | |
total_salary = sum(salary) - min_salary - max_salary | |
num_employees = len(salary) - 2 | |
return total_salary / num_employees |